A bag has 1 red marble, 4 blue marbles, and 3 green marbles. Peter draws a marble randomly from the bag, replaces it, and then draws another marble randomly. What is the probability of drawing 2 blue marbles in a row? Explain your answer. (pls) :)

8 marbles in the bag

1/2 of the bag is blue marbles

So there is a 50 percent chance of drawing a blue marble the first time.

And a 50 percent chance of drawing a blue marble the second time.

This means there is a 25 percent chance of drawing 2 blue marbles in a row.

*Not a 100% sure this answer is correct, but I tried my best.

1/4

Step-by-step explanation:

because A 50% chance the first time and a 50% chance the second time

or if you want a full-on explanation...

The chances of drawing one of the 4 blue marbles out of a bag of 8 total marbles are 4/8 (or 50% or 0.50).

Peter puts the marble back (making 8 once more).

Now, the chances of him drawing one of the 4 blue marbles out of a bag of 8 total marbles are again 50% (if we don't care about what he got the first time, but we do!).  Since the chances of drawing two blue marbles in successive draws are 50% of 50% (or 1/2 of 1/2).  "Of" usually means multiply, so the probability is 0.25.

i hope this helps some what!

is there any attachment? what are the equations?

not solvable

step-by-step explanation:

we need more information, or at least an