Afunction f satisfies the following conditions: f(5)=20, f'(5)=2, and f"(x)< 0, for x> =5. which of the following are possible values for f(7)? possible choices are 28, 20, 26, 24, 22

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

do have an equation or graph or

step-by-step explanation: