Determine if the biconditional is true. If false, give a counterexample. "A figure is a square if and only if it is a rectangle."

A. The biconditional is true.

B. The biconditional is false. A rectangle does not necessarily have four congruent sides.

C. The biconditional is false. All squares are parallelograms with four 90° angles.

D. The biconditional is false. A rectangle does not necessarily have four 90° angles.

a

step-by-step explanation:

rurbrbrjrnrbjr

y -5 = (-1/4)(x + 8)

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

using pemdas, (order of operations) you'll see the answer is 24.