Snooker is a kind of pool or billiards played on a 6-foot-by-12-foot table. the side pockets are halfway down the rails (longside)
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find the distance, to the nearest tenth of an inch, diagonally across from the corner pocket to side pocket

The answer is 101.76 in

Let length be 12 ft (l = 12 ft) and width be 6 ft (w = 6ft).
The side pocket will be on the half of its length (l). To calculate the distance, we will use the distance d as a hypotenuse of the right triangle with sides w and l/2.
According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of two other sides:
d² = w² + (l/2)²

We have:
d = ?
w = 6 ft
l = 12 ft

d² = 6² + (12/2)²
d² = 6² + 6²
d²= 2 * 6²
d² = 2 * 36
d² = 72
d = √72
d = 8.48 ft

Since 1 ft is 12 in, then 8.48 ft is 101.76 in:
8.48 * 12 in = 101.76 in

Idon’t have want a lot more