Mathematics, 01.04.2021 16:40 MendesArmy333

Tennis Replay In the year that this exercise was written, there were 879 challenges made to referee calls in professional tennis singles play. Among those challenges, 231 challenges were upheld with the call overturned. Assume that in general, 25% of the challenges are successfully upheld with the call overturned. a. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is exactly 231. b. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is 231 or more. If the 25% rate is correct, is 231 overturned calls among 879 challenges a result that is significantly high

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Answer from: soevse

a. 0.0209 = 2.09% probability that among the 879 challenges, the number of overturned calls is exactly 231.

b. 231 is less than 2.5 standard deviations above the mean, which means that 231 overturned calls among 879 challenges is not a significantly high result.

Step-by-step explanation:

For each challenge, there are only two possible outcomes. Either it was overturned, or it was not. The probability of a challenge being overturned is independent of any other challenge. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Significantly high:

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

If a value is more than 2.5 standard deviations above the mean, this value is considered significantly high.

25% of the challenges are successfully upheld with the call overturned.

This means that p = 0.25

879 challenges

This meas that n = 879

a. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is exactly 231.

This is P(X = 231). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 231) = C_{879,231}.(0.25)^{231}.(0.75)^{648} = 0.0209$

0.0209 = 2.09% probability that among the 879 challenges, the number of overturned calls is exactly 231.

b. If the 25% rate is correct, find the probability that among the 879 challenges, the number of overturned calls is 231 or more. If the 25% rate is correct, is 231 overturned calls among 879 challenges a result that is significantly high

The mean is:

E(X) = np = 879*0.25 = 219.75

The standard deviation is:

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{879*0.25*0.75} = 12.84$

219.75 + 2.5*12.84 = 251.85 231

231 is less than 2.5 standard deviations above the mean, which means that 231 overturned calls among 879 challenges is not a significantly high result.

Answer from: Quest

answer: the area of the parallelogram below is 42 square meters.

- officialprodixy ☕

Answer from: Quest

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get $6x^{2} -3x$

and solving the given expression :

3x(2x-1)

$6x^{2} -3x$

since solving the expression using tiles and solving the expression algebraically we get the same answer

thus we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

Which is true regarding armando’s use of algebra tiles? he used the algebra tiles correctly. he did

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Tennis Replay In the year that this exercise was written, there were 879 challenges made to referee...