What is the measure of arc CD?
A. 124
B. 62
C. 64
D. 60
Help plz!

Option D

Step-by-step explanation:

By inscribed angle theorem,

" Measure of an inscribed angle by the arc measures half of the measure of the arc"

m(arc BCD) = 2m(∠BED)

And m(arc BCD) = m(arc BC) + m(arc CD)

m(arc BC) + m(arc CD) = 2m(∠BED)

64° + m(arc CD) = 2(62°)

m(arc CD) = 124 - 64

                 = 60°

Option D is the answer.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.