Mathematics, 01.04.2021 17:40 wolfgirl4762

(x - 6)2 + (y + 5)2 = 16 In the xy-plane, the graph of the equation above is a
circle. Point P is on the circle and has coordinates
(10,-5). If PQ is a diameter of the circle, what are
the coordinates of point Q?
A) (2,-5)
B) (6,-1)
C) (6,-5)
D) (6,-9)

Answers: 1

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(x - 6)2 + (y + 5)2 = 16 In the xy-plane, the graph of the equation above is a
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(x - 6)2 + (y + 5)2 = 16 In the xy-plane, the graph of the equation above is a circle. Point P is on the circle and has coordinates (10,-5). If PQ is a diameter of the circle, what are the coordinates of point Q? A) (2,-5) B) (6,-1) C) (6,-5) D) (6,-9)

Answers

Another question on Mathematics

(x - 6)2 + (y + 5)2 = 16 In the xy-plane, the graph of the equation above is a
circle. Point P is on the circle and has coordinates
(10,-5). If PQ is a diameter of the circle, what are
the coordinates of point Q?
A) (2,-5)
B) (6,-1)
C) (6,-5)
D) (6,-9)