Write an equation in standard form for the line that has slope 1/3 and passes
through (-2, 8)

Step-by-step explanation:

The equation of a line which passes through (x₁, y₁) and with slope of m in point-slope form:

                              y - y₁ = m(x - x₁)

m = ¹/₃

(-2, 8)    ⇒   x₁ = -2,  y₁ = 8

Therefore,  the equation of the line which passes through (-2, 8) and with slope of 1/3 in point-slope form:

y - 8 = ¹/₃(x - (-2))

y - 8 = ¹/₃x + ²/₃                   {multiply both sides by 3}

3y - 24 = x + 2                    {subtract x from both sides}

-x + 3y - 24 = 2                     {add 24 to both sides}

-x + 3y = 26

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

b

step-by-step explanation: