Calculate the area of triangle WXY with altitude YZ, given W(2, −1), X(6, 3), Y(7, 0), and Z(5, 2). (6 points) 8 square units

9.4 square units

7.7 square units

12 square units

(c, 0) i might be wrong so don't put full faith on my answer

5+2x=a

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answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92