The attendance at a baseball game was 400 people. Adult seats sold for $15 and children seats sold for $10. Total ticket sales were $4560. How many of each type of ticket were sold?

112 adult and 288 children

Step-by-step explanation:

x= adult seats

y= children seats

15x + 10y = 4560

x + y = 400 --> y=400-x

so plug 400-x for y in the other equation

15x + 10(400-x)= 4560

now solve this equation

15x + 10(400-x)= 4560 --> 15x + 4000-10x= 4560 --> 15x -10x = 560 --> 5x=560 --> x = 560/5 --> x= 112

now plug in 112 for this equation (x+y=400) --> 112+y=400 --> y= 288

homozygous. one is homozygous, while two is heterozygous.

a

step-by-step explanation: