Write the equation of the line which passes through (1, 2) and with slope of −1/3 in standard form.

Step-by-step explanation:

The equation of a line which passes through (x₁, y₁) and with slope of m in point-slope form:

                                y - y₁ = m(x - x₁)

m = -¹/₃

(1, 2)    ⇒   x₁ = 1,  y₁ = 2

Therefore,  the equation of the line which passes through (1, 2) and with slope of −1/3 in point-slope form:

y - 2 = -¹/₃(x - 1)

y - 2 = -¹/₃x + ¹/₃                     {add ¹/₃x to both sides}

¹/₃x + y - 2 = ¹/₃                     {add 2 to both sides}

¹/₃x + y = 2¹/₃                       {multiply both sides by 3}

x + 3y = 7            

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen