If -2 < x < -1 then which of the following orders x , x^2 , and x^3 from least to greatest? A. x < x^2 < x^3
B. x^2 < x^3 < x
C. x^3 < x < x^2
D. x < x^3 < x^2
E. x^3 < x^2 < x

The Answer is C

Step-by-step explanation:

we know that x is a negative number since it is between -1 and -2. A negative number cubed will be a negative number and since we're multiplying, x^3 will be less than x. A negative number squared will be positive, thus x^2 is the greatest.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: