PLEASE HELP GUYS! Will give brainliest for answers F(x)=
x^7+x^6+2x^5+8x^4+2x^3-3

1. What are the zeros
(x-intercept) need a minimum of 3:

2. Relative (local) minimums and maximums:

3. What does your end behavior resemble (x^2,-x^2,x^3 or -x^3)

4. The number of turning points in the graph:

5. State the intervals of increasing and decreasing:

are the 1,2,3,4,5 suppose to be question's???

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

sorry, i'm new here and i'm just trying to figure this out. try quizlet. rate 5* you!