Please help with questions 2,3, and 4

2) d

3) c

4) d

Step-by-step explanation:

2- the coefficient of the leading term (the x that has the highest degree) need to be + which is only found in d

so the answer is d

3- I just graphed the equations and then looked whether or not they have an axis of symmetry at x=1

a does have an axis of symmetry at x=1

b does have an axis of symmetry at x=1

c does not have an axis of symmetry at x=1

d does have an axis of symmetry at x=1

so the answer is c

4-

a is wrong bc the the coefficient of the leading term is - so it will open downward.

b is wrong bc it's vertex is actually equal to (2,50)

c is wrong bc it's axis of symmetry is actually equal to x=2

d is correct bc since the graph is opening downward it will have a max point

so the answer is d

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

college