Kathleen successfully solved the system of equations 4x+3y=15 and −5x−2y=−24
by multiplying each equation by a constant and adding the two equations together to eliminate the x
-terms. She then solved for y
and substituted the value of y
back into one of the equations and solved for x
. What could she have multiplied each equation by, and what was her final answer?

A. She could have multiplied the first equation by 4 and the second equation by 5, getting a final answer of x=−3
and y=6.

B. equation by 5
and the second equation by 4, getting a final answer of x=−3 and y=6.

C. She could have multiplied the first equation by 4
and the second equation by 5, getting a final answer of x=6 and y=−3.

D. She could have multiplied the first equation by 5
and the second equation by 4, getting a final answer of x=6 and y=−3.