One of the measures of a triangle is 30º. If the sum of the other 2 angles is 150º and the differnce their measures is 18º what are the of the unkown angles

84° & 66°

Step-by-step explanation:

find our variables...

difference in two unknown angles is 18 so...

Let's use a, b, & c to set up

a=30 b=b c=b-18

150=b+c

150=b+(b-18)

150=2b-18

168=2b

84=b

Use our known b to find c...

c=b-18

c=84-18

c=66

Adding all three up to make sure they give us 180 degrees is a good way to check our work.

a+b+c=

30+84+66=180

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66answer:

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐