A tree that is 4 ft tall is growing at a rate of 1 ft each year a tree that is 12 feet tall is growing at a rate of 1/2 ft each year how many years will it take the two trees to reach the same height

16 years

Step-by-step explanation:

Given data

For the first tree

let the expression for the height be

y=4+x1

where y= the total height

          4= the initial height

          x= the number of years

For the second tree, the expression is

y=12+0.5x2

Equate 1 and 2

4+x=12+0.5x

x-0.5x=12-4

0.5x= 8

x= 8/0.5

x=16

Hence it will take 16 years for both trees to have the same height

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

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