A survey was given to a random sample of 650 voters in the United States to ask about their preference for a presidential candidate. Of those surveyed, 50% of the people said they preferred Candidate A. At the 95% confidence level, what is the margin of error for this survey expressed as a percentage to the nearest tenth? (Do not write \pm±).

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

i think the correct option is the second option.

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%