What is the center of the circle: (x-2)^2+(y-4)^2=25 ?

The center of this circle is at (2, 4).

Step-by-step explanation:

Compare the given equation to the standard equation of a circle with center at (h, k) and radius r:

(x - h)^2 + (y - k)^2 = r^2

(x - 2)^2 + (y - 4)^2 = 5^2

Through this comparison we see that h = 2, k = 4 and r = 5.

The center of this circle is at (2, 4).

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3