()) A rectangular piece of paper has a perimeter of 22 inches and an area of 28 square inches. What are the dimensions of the paper?

Given:

Perimeter of a rectangular paper = 22 inches.

Area of the rectangular paper = 28 square inches.

To find:

The dimensions of the rectangular paper.

Solution:

Let l be the length and w be the width of the rectangular paper.

Perimeter of a rectangle is:

Perimeter of a rectangular paper is 22 inches.

                     ...(i)

Area of a rectangle is:

Area of the rectangular paper is 28 square inches.

Using (i), we get

Splitting the middle term, we get

Using zero product property, we get

If , then by using (i)

If , then by using (i)

Therefore, the dimensions of the paper are either or .

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5