A bag of color tiles contains 2 red, 1 blue, 1 green, and 4 yellow. Sean reaches in and draws one tile without replacing it. He then draws a second tile and a third tile without replacing them. Which
of the following combinations is a possible draw?
F:red, blue, blue G:red, green, green H:yellow, blue, green J:blue, blue, green

H

Step-by-step explanation:

Since there is 4 yellows, 1 green, and 1 blue, there is no way you could draw 2 blues or 2 greens. Therefore, F, G, and J are immediately eliminated. The only answer left is H, and it makes sense. H is the answer.

H: yellow, blue, green

Step-by-step explanation:

F: red, blue, blue = cannot be true as there is 1 blue tile in bag and it cannot be drawn twice without replacing first draw.

G: red, green, green = cannot be true because 1 original green tile in bag cannot be drawn twice

J: blue,blue, green = cannot be true for same reason; 1 original blue tile cannot be drawn twice without replacement.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

34

step-by-step explanation: