Find the area of ​​the parallelepiped whose sides belong to the straight lines r: 2y = x + 4
s: y = 3x-3
t: y + 1 = x / 2
v: y = 3x + 5

Please can someone be kind enough to solve this question. Thank you

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.