If the roots of the given quadratic equation are real and equal then find the value of ‘m’.

(m-12) x2 + 2 (m-12) x + 2 = 0​

m = (12 x^2 + 24 x - 2)/(x^2 + 2 x)

Step-by-step explanation:

Solve for m:

2 + 2 x (m - 12) + x^2 (m - 12) = 0

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand and collect in terms of m:

2 - 24 x - 12 x^2 + m (x^2 + 2 x) = 0

Hint: | Isolate terms with m to the left hand side.

Subtract -12 x^2 - 24 x + 2 from both sides:

m (x^2 + 2 x) = 12 x^2 + 24 x - 2

Hint: | Solve for m.

Divide both sides by x^2 + 2 x:

m = (12 x^2 + 24 x - 2)/(x^2 + 2 x)

5+2x=a

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