Hi I need help in this question

First part representing requirements for the length x>=5 ft

Second part yes

Step-by-step explanation:

Well, the formula for finding the area of a rectangle is l x w. In the question, it states that the pen must be 4 ft wide and to fit his requirements of the pen being at the minimum 20 ft^2 we have this inequality 4x>=20 which we must solve and we get x>=5 which means that this represents all of the possible lengths for the play space. For the second part, we know that to fufill Judah's requirements for square ft., our length must be greater than or equal to 5. Last time I was doing math, I'm pretty sure 5 1/2>5 which thus can be accepted as a length value, still meeting the requirements of at least 20ft^2 space for the play space.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6