Given: Angle 0 is in quadrant III and sin0 = -sqrt(6)/4

Prove: cos0 = -sqrt(10)/4

Below.

Step-by-step explanation:

The cosine is also negative in Quadrant III.

sin^2 O + cos^2 O = 1

cos^2 O = 1 - sin^2 O

= 1 - (-sqrt(6)/4)^2

= 1 -  (6/16)

=  16/16 - 6 /16

= 10/16

So cos O = -sqrt(10/16)

= -sqrt(10)/4.

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

no one knows lol

step-by-step explanation: