What is the volume of a cone that has a radius of 9 inches and a height of 16​ inches? Use 3.14 for pi. Flip it here's the 1356.48 inch^3
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a² + b²= c²

24² + 7² = c²

c= 25

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16

simplifying

7ln(x + 2.8) = 11.2

reorder the terms:

7ln(2.8 + x) = 11.2

(2.8 * 7ln + x * 7ln) = 11.2

(19.6ln + 7lnx) = 11.2

solving

19.6ln + 7lnx = 11.2

solving for variable 'l'.

move all terms containing l to the left, all other terms to the right.

reorder the terms:

-11.2 + 19.6ln + 7lnx = 11.2 + -11.2

combine like terms: 11.2 + -11.2 = 0.0

-11.2 + 19.6ln + 7lnx = 0.0

the solution to this equation could not be determined.

step-by-step explanation:

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