Which equation represents a circle with a center at -3, -5) and a radius of 6 units? O (x - 3)2 + (-5)2 = 6
0 (x - 3)2 + (-5)2 = 36
O (x + 3)2 + (y + 5)2 = 6
(x + 3)2 + (y + 5)2 = 36
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(x+3)²+(y+5)² = 36

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the centre of the circle

r is the radius of the circle

Given

Centre (-3, -5)

a = -3 and b = -5

radius r = 6units

Substitute

(x-a)²+(y-b)² = r²

(x-(-3))²+(y-(-5))² = 6²

(x+3)²+(y+5)² = 36

hence the required equation is (x+3)²+(y+5)² = 36

b

step-by-step explanation:

where are the images of the functions i can only see the question you typed.

step-by-step explanation: