[related rates]

each side of a square is increasing at a rate of 6 cm/s. at what rate is the area of the square increasing when the area of the square is 16 cm^2?

Below is the solution: 

A(final)=16cm^2 ds/dT=6 da/dT=? 

A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm 

da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm) 

Answer should be da/dT=48cm^2/sec

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