Determine whether the infinite geometric series is convergent or divergent. if it is convergent, find its sum. (if the series is divergent, enter divergent.)

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The geometric series can be rewritten as
1 + (-1/6) + (-1/6)^2 + (-1/6)^3 + ...
Since the magnitude of the common ratio is less than 1. The series is then convergent and it has a sum.
S = a/(1-r) = 1/(1+1/6) = 6/7

I hope my answer has come to your help.

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