If the integral of f(x)dx = 2.3 from 1 to 3 and f'(x) = f(x), what is the value of f(3) - f(0). the graph will be inserted as a picture.

F(3)−F(0)=∫30f(x)dx
so it looks like 2.3+1=3.3

I think you forgot to add the attachment. But I did some research. The correct answer to this question is 2.3 + 1 = 3.3. To solve this, If f(x)dx = 2.3 and F' (x) = f(x), 

F(3) − F(0) = 30f(x)dx 
2.3 + 1 = 3.3. This is the value of F(3) - F(0).

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.