+12x
3
+20x
2
Mathematics, 06.04.2021 23:20 malaysiasc93
The rectangle below has an area of 8x^5+12x^3+20x^28x
5
+12x
3
+20x
2
8, x, start superscript, 5, end superscript, plus, 12, x, cubed, plus, 20, x, squared.
The width of the rectangle is equal to the greatest common monomial factor of 8x^58x
5
8, x, start superscript, 5, end superscript, 12x^312x
3
12, x, cubed, and 20x^220x
2
20, x, squared.
What is the length and width of the rectangle?
Answers: 3
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You know the right answer?
The rectangle below has an area of 8x^5+12x^3+20x^28x
5
+12x
3
+20x
2
+12x
3
+20x
2
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