A large shipment of video streaming devices is accepted upon delivery if an inspection of 20 randomly selected video streamingdevices yields no more than 1defective item. a.Find the probability that the shipment is accepted if 3% of the total shipment is defective. b.Find the probability that the shipment is accepted if 15% of the total shipment is defective.

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b

0.2cm < 1.5cm : 0.2cm > 1.5cm