Calculate dy/dx
you need not expand your answer.

y=3x^2-9x+13/2x+4

The solution to the problem is as follows:

The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know} 

let f(x)=9x +13 and g(x)=2x+4 

f'(x)=9 and g'(x)=2 

therefore just substitute the equations in. 

y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2)) 


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The variables should add up to equal 1