A regular dodecagon P_1 P_2 P_3 \dotsb P_{12} is inscribed in a circle with radius 1. Compute (P_1 P_2)^2 + (P_1 P_3)^2 + \dots + (P_{11} P_{12})^2.(The sum includes all terms of the form (P_i P_j)^2, where 1 \le i < j \le 12.)

Hint(s): Sums of squares of lengths should make you think of what?

There is no graph to go along with this

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.