Rectangle A has area 50 cm2 and length 10 cm. The area of rectangle B is one-half the area of rectangle A. The rectangles have the same length.
What is the width of rectangle B?

5/2

Step-by-step explanation:

so to find the area of a rectangle it is width x length

10=Length

w=Width

10w=50

w=5cm=width

1/2(area of rectangle A)

1/2(50)=25

w(length of Rectangle A)=area

w(10)=25

w=25/10

w=5/2

Hope that helps :)

Area of rectangle A = 50

l × b = 50

10 × b = 50

b = 50/10 = 5cm.

Now,

Area of rectangle B = 50/2

l × b = 25

10 × b = 25

b = 25/10 = 2.5cm

are you an artist's daughter? cuz dang you a fine piece of art, girl.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)