Match the range of the function f(x)=x^2+2x-1 to its domain
2
-2
3
-3

See solutions below

Step-by-step explanation:

Match the range of the function f(x)=x^2+2x-1 to its domain

Domains of the function are the input values x i.e 2, -2, 3 and 3

corresponding f(x) for each values are the range

when x = 2

f(2)=2^2+2(2)-1

f(2) = 4 + 4 - 1

f(2) = 7

when x = -2

f(-2)=(-2)^2+2(-2)-1

f(-2) = 4 - 4 - 1

f(-2) = -1

when x = 3

f(3)=3^2+2(3)-1

f(3) = 9 + 6 - 1

f(3) = 14

when x = -3

f(-3)=(-3)^2+2(-3)-1

f(-3) = 9 -6 - 1

f(-3) = 2

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

part a: 1.08

part b: 27.59