Given the triangle shown here, the first steps in the proof of the law of sines are:
a. set sina = b/k and sinb = k/a and solve for k in both equations.
b. set sina = k/b and sinb = a/k and solve for k in both equations.
c. set sina = -k/b and sinb = -k/a and solve for k in both equations.
d. set sina = k/b and sinb = k/a and solve for k in both equation.

goog may be able to you find that answer

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180