A flying squirrel jumped from a tree 11 feet in the air at an initial velocity of 9 feet per second. The equation h=−2t^2+9t+11 models his jump where h is height in feet and t is time in seconds. What was the squirrel's maximum height?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

plz yuo

step-by-step explanation: