On a certain hot summer's day, 321 people used the public swimming pool. The daily prices are $1.75 for children and $2.00 for adults. The receipts for admission totaled $634.25. How many children and how many adults swam at the public pool that day?​

31 children and 290 adults

Step-by-step explanation:

Let a = number of adults and c = number of children.

a + c = 321

2a + 1.75c = 634.25

Multiply both sides of the the first equation by -2 and add it to the second equation.

         -2a -     2c = -642

(+)       2a + 1.75c = 634.25

                 -0.25c = -7.75

Divide both sides by -0.25

c = 31

Use the first equation to find a.

a + c = 321

Substitute 31 for c.

a + 31 = 321

Subtract 31 from both sides.

a = 290

31 children and 290 adults

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

109 is the nearest whole number/final answer! : )