Can someone help me out with these equations?
1. (5+ √3)^2
2. (√6-5√3)^2
3. (6+3√2)^2

9514 1404 393

Step-by-step explanation:

It is useful to remember the form for the square of a binomial.

  (a +b)² = a² +2ab +b²

  (a -b)² = a² -2ab +b²

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1. (5 +√3)² = 5² +2·5·√3 +(√3)² = 25 +10√3 +3

  = 28 +10√3

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2. (√6 -5√3)² = (√6)² -2·√6·5√3 +(5√3)² = 6 -30√2 +75

  = 81 -30√2

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3. (6 +3√2)² = 6² +2·6·3√2 +(3√2)² = 36 +36√2 +18

  = 54 +36√2

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.