A ball is thrown directly upward from a height of 5 ft with an initial velocity of 24 ft/sec. The function s(t) = -16t^2+24t+5 gives the height of the ball, in feet, t seconds after it has been thrown. Determine the time at which the ball reaches its maximum height and find the maximum height.​

The maximum height is 14 feet and it will take 0.75 s to reach there.

Step-by-step explanation:

A ball is thrown directly upward from a height of 5 ft with an initial velocity of 24 ft/sec.

The function is :

....(1)

It gives the height of the ball, in feet, t seconds after it has been thrown.

For maximum height,

s'(t) = 0

So,

-32t+24 = 0

t = 0.75 s

It will take 0.75 s to reach the maximum height.

Put t = 0.75 s in equation (1). So,

So, the maximum height is 14 feet and it will take 0.75 s to reach there.

x/3-10=8

x/3=18

x=48

1,8,15,22,29,36,43,50

step-by-step explanation: