A football is kicked into the air. The height of the football can be modeled by the equation h = -16x^2 + 16x, where h is the height reached by the ball after x seconds. When does the
ball touch the ground?

x = 0 and x = 1

Step-by-step explanation:

Given that,

A football is kicked into the air. The height of the football can be modeled by the equation :

Where

h is the height reached by the ball after x seconds

When it touches the ground, h = 0

So,

So, it will touch the ground at x = 0 and x = 1 seconds.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

96 39 cause 135 -96=39 im smart (i used a calculater)