Write the formula for the parabola that has x- intercepts (1.3,0) and (-1.3,0), and y- intercept (0,169).

Step-by-step explanation:

et me start by the following correction:

The y intercept is (0,1.69) and not (0,169)

So the intercept form of the quadratic equation is y=a(x-p)(x-q)

where (-1.3,0)=(p,0) and (1.3,0) is (q,0); then p=-1.3, and q=1.3

With the vertex being at the y axis and the intercepts at the x axis means that the parabola opens down. then 1.69=a(0+1.3)(0-1.3), 1.69=-1.69 a, a=-1

Substituting, y=-1(x+1.3)(x-1.3) note that this is difference of two squares y=-[x2-(1.3)2] , y=-(x2-1.69), y=-x2+1.69

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b