Can someone help me ​

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  1. 5000

  2. the year is 2003

  3. > 1000; evaluate the function

Step-by-step explanation:

1. The value of t is "years since 2005." In 2005, the value of t is zero. To find the model's prediction for 2005, substitute t=0.

  p = 5000·2^0 = 5000·1

  p = 5000 . . . . in 2005

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2. When t=-2, it means you're concerned with the population 2 years before 2005. That is, you are modeling the population in 2003.

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3. Evaluate the function for t=-2:

  p = 5000·2^(-2) = 5000·1/4 = 1250

For t=-2, the fish population is 1250, which is more than 1000.

noncoplanar points are points that do not lie on the same line.