A lamina with density (x; y) = 10y (x 2 + y 2 ), occupies the region inside the circle x 2 + y 2 = 2x and outside the circle x 2 +y 2 = 1, inside the Örst octant. Find the mass of the lamina. (a) Set us the integral, in rectangular (cartesian) coordinates, of the mass of this lamina. Do not integrate. (b) Set up the integral from (a) in terms of polar coordinates. Do not integrate. (c) Integrate the easier of (a) and (b)

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

i believe it is the square root of 122 because when you turn it on it's side, to where the 5 inches is on the bottom, it looks like it is the same length.

answer is a.

13.268

hope you get it right.