Figure 1 has 3 boxes and figure 2 has 5 boxes, it increases 2 boxes each figure. What figure number will have 42 boxes?

None of them

Step-by-step explanation:

3, 5, 7, 9, ... they are all odd numbers

42 is an even number, it will never be 42

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer:

step-by-step explanation: