Read the passage from A Doll's House.
Helmer: [calls out from his room]. Is that my little lark
How do the stage directions in brackets affect the
meaning of the text?
twittering out there?
Nora: [busy opening some of the parcels]. Yes, it is!
O They tell the reader that Torvald opens his door only
when
he realizes that Nora has spent money.
Helmer Is it my little squirrel bustling about?
They tell the reader that Torvald uses pet names for
Nora: Yes!
Nora and treats her like a child.
Helmer: When did my squirrel come home?
O They show the reader that Torvald thinks that Nora
bought too much
Nora: Just now. [Puts the bag of macaroons into her
O They show the reader that Torvald prefers his pets
pocket and wipes her mouth.] Come in here, Torvald,
over his wife.
and see what I have bought.
Helmer: Don't disturb me. [A little later, he opens the
door and looks into the room, pen in hand.] Bought, did
you say? All these things? Has my little spendthrift
been wasting money again?
Nora: Yes but, Torvald, this year we really can let

Which of the fallowing best completes the sequence 12,8,5, a) 1 b) 2 c)4 d)0

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.

Drag each equation to the correct location on the table. for each equation, determine the number of solutions and place on the appropriate field in the table.