The graph of y = Ab^x, where A and b are constants, passes through (2, 2) and
(5, 16). Find the value of A and of b.

A = 1/2, b = 2

Step-by-step explanation:

Inputting (x, y) into y = Ab^x we know that

point (2, 2):

2 = Ab^2

point (5, 16):

16 = Ab^5

So:

16/2 = Ab^5 / Ab^2

8 = b^3

b = 2

Now inputting point (2, 2) with b = 2

2 = A*2^2

2 = 4A

A = 1/2

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )