Mathematics, 09.04.2021 17:50 joebiden1
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You throw a baseball from 6 feet above the ground with an initial vertical velocity of 38 feet per second. Your friend catches the ball at a height of 2 feet. The equation below models the height of the ball as a function of time. HOW LONG IS THE BALL IN THE AIR? (Round to the nearest hundredth of a second,
y=-16x^(2)+38x+6
You throw a baseball from 6 feet above the ground with an initial vertical velocity of 38 feet per second. Your friend catches the ball at a height of 2 feet. The equation below models the height of the ball as a function of time. FIND THE MAXIMUM HEIGHT OF THE BALL? (Round to the nearest tenth of a foot
y=-16x^(2)+38x+6
Answers: 3
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