A sphere with a radius of 21cm JUST fits in a cube-shaped box. Calculate the amount of empty space in the box rounded to the nearest tenth of a cubic centimetre. How do you solve this?

Since its a cube and a sphere just fits in side it we know that both the sphere and the cube are 21cm wide and since its a cube the dimensions of the cube is 21*21*21 giving you 9,261 cm³ then you find the volume of the V=4/3π10³≈4849.04826 now all you have to do is subtract your two totals to get 4411.95174

Step-by-step explanation:

Brₐinliest plz

35,295.6 cm^3 to the nearest tenth.

Step-by-step explanation:

The diameter of the sphere = 2*21 = 42.

The volume of the box = 42^3 ( because the dimensions of the box = the diameter of the sphere).

The volume of the sphere = 4/3 π r^3

= 4/3 π 21^3

So the empty space = 42^3 - 4/3 π 21^3

= 35295.615 cm^3.

l.jnl.j/n.m,lm,

step-by-step explanation: